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Hi, I have got a new Seagate 160GB Harddisk (ST3160023A). I need to make my PC to have Multiple Operating systems with a Multi-boot menu in the startup. The OS should include: 1) Windows 98 SE 2) Windows 2000 Advanced Server 3) Windows 2003 Eval Edition 4) Red Hat Linux 9.0 What would be the best way to partition my harddisk to accomodate all the above. I also need to have some free drives where I can store my DATA + PROGAMS + MUSIC + MOVIES that can be accessed from all the above OS. Some of the Operating Systems ...
Hi,
I have got a new Seagate 160GB Harddisk (ST3160023A). I need to make
my PC to have Multiple Operating systems with a Multi-boot menu in the
startup. The OS should include:
1) Windows 98 SE
2) Windows 2000 Advanced Server
3) Windows 2003 Eval Edition
4) Red Hat Linux 9.0
What would be the best way to partition my harddisk to accomodate all
the above. I also need to have some free drives where I can store my
DATA + PROGAMS + MUSIC + MOVIES that can be accessed from all the
above OS.
Some of the Operating Systems are not recognizing the full disk space.
Please let me know what all Software Drivers/Updates I need to use in
all the operating system to make use of the entire 160GB space.
FYI, I am using Intel 845 Chipset (Pentium 4 - 2.4GHz). My RAM is
DDR-256MB.
Thanks,
Kamlesh
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Thanks for the information.
I have installed Intels Application Accelerator.
In my Win2000 Computer Management -> Disk Management Option, the drive
size is shown as 149.9 GB. Is this correct? I was told that this
harddisk is 160GB, then why am I shown 149.9GB in Win2000?
mjt <com> wrote in message news:<_FQrb.19993$news.atl.earthlink.net>...
>
> 1) make a primary partition large enough to hold win98se
> 2) create an extended partition
> 3) create a logical partition large enough for win2kas
> 4) create a logical partition large enough for win2003ee
> 5) create a logical fat32 partition for sharing, large
> enough to hold the data
> 5) create a logical partition large enough for RH 9.0
> .[/ref]
On 10 Nov 2003 21:09:11 -0800,
Kamlesh <com> wrote:
Please don't top post.
149.9 GB = 1.609539e+11 bytes which is roughly 160,953,900,000 bytes.
Michael C.
--
com http://mcsuper5.freeshell.org/
Registered Linux User #303915 http://counter.li.org/
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