#38974 [NEW]: array should throw warning

[hendlerman at yahoo dot com]

From: hendlerman at yahoo dot com
Operating system: windows XP
PHP version: 5.1.6
PHP Bug Type: Arrays related
Bug description: array should throw warning

Description:
------------
The error is caused by a user error, but I believe PHP should be throwing
an error. PHP is not strongly typed, but I thought you get a warning if
you try to convert a string to an array.

Sorry I am not in 5.1.6


Reproduce code:
---------------
/**
* Output for me
* PHP version 5.1.4
* Array ( [name] => 2alue )
*
* */
function array_bug()
{
echo "PHP version ". phpversion().'<br />';
$test_array = array();

$test_array['name'] = 'value';
$test_array['name']['count'] = 2;

print_r($test_array);
}

array_bug(); exit;

Expected result:
----------------
I would expect an error or warning

Actual result:
--------------
Array ( [name] => 2alue )

--
Edit bug report at [url]http://bugs.php.net/?id=38974&edit=1[/url]
--
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[tony2001@php.net]

ID: 38974
Updated by: [email]tony2001@php.net[/email]
Reported By: hendlerman at yahoo dot com
Status: Bogus
Bug Type: Arrays related
Operating System: windows XP
PHP Version: 5.1.6
New Comment:

$string[0] = 'c'; is perfectly valid code and that's what you get with
$string['otherstring'].


Previous Comments:
------------------------------------------------------------------------

[2006-09-27 14:53:23] [email]derick@php.net[/email]

Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
[url]http://www.php.net/manual/[/url] and the instructions on how to report
a bug at [url]http://bugs.php.net/how-to-report.php[/url]

..

------------------------------------------------------------------------

[2006-09-27 14:47:10] hendlerman at yahoo dot com

Description:
------------
The error is caused by a user error, but I believe PHP should be
throwing an error. PHP is not strongly typed, but I thought you get a
warning if you try to convert a string to an array.

Sorry I am not in 5.1.6


Reproduce code:
---------------
/**
* Output for me
* PHP version 5.1.4
* Array ( [name] => 2alue )
*
* */
function array_bug()
{
echo "PHP version ". phpversion().'<br />';
$test_array = array();

$test_array['name'] = 'value';
$test_array['name']['count'] = 2;

print_r($test_array);
}

array_bug(); exit;

Expected result:
----------------
I would expect an error or warning

Actual result:
--------------
Array ( [name] => 2alue )


------------------------------------------------------------------------


--
Edit this bug report at [url]http://bugs.php.net/?id=38974&edit=1[/url]

[hendlerman at yahoo dot com]

ID: 38974
User updated by: hendlerman at yahoo dot com
Reported By: hendlerman at yahoo dot com
Status: Bogus
Bug Type: Arrays related
Operating System: windows XP
PHP Version: 5.1.6
New Comment:

I understand that it's valid in PHP to overwrite the string with an
array. The problem is that the string is not actually overwritten by
the array. I thought that was clear from the sample code!

Doesn't seem like a feature if the array isn't overwritten. Perhaps I
should have titled = "String is not properly overwritten "


Previous Comments:
------------------------------------------------------------------------

[2006-09-27 14:54:23] [email]tony2001@php.net[/email]

$string[0] = 'c'; is perfectly valid code and that's what you get with
$string['otherstring'].

------------------------------------------------------------------------

[2006-09-27 14:53:23] [email]derick@php.net[/email]

Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
[url]http://www.php.net/manual/[/url] and the instructions on how to report
a bug at [url]http://bugs.php.net/how-to-report.php[/url]

..

------------------------------------------------------------------------

[2006-09-27 14:47:10] hendlerman at yahoo dot com

Description:
------------
The error is caused by a user error, but I believe PHP should be
throwing an error. PHP is not strongly typed, but I thought you get a
warning if you try to convert a string to an array.

Sorry I am not in 5.1.6


Reproduce code:
---------------
/**
* Output for me
* PHP version 5.1.4
* Array ( [name] => 2alue )
*
* */
function array_bug()
{
echo "PHP version ". phpversion().'<br />';
$test_array = array();

$test_array['name'] = 'value';
$test_array['name']['count'] = 2;

print_r($test_array);
}

array_bug(); exit;

Expected result:
----------------
I would expect an error or warning

Actual result:
--------------
Array ( [name] => 2alue )


------------------------------------------------------------------------


--
Edit this bug report at [url]http://bugs.php.net/?id=38974&edit=1[/url]

[hendlerman at yahoo dot com]

ID: 38974
User updated by: hendlerman at yahoo dot com
-Summary: array should throw warning
Reported By: hendlerman at yahoo dot com
-Status: Bogus
+Status: Open
Bug Type: Arrays related
Operating System: windows XP
PHP Version: 5.1.6
New Comment:

Changing title and re-opening so it gets reviewed again.


Previous Comments:
------------------------------------------------------------------------

[2006-09-27 15:14:18] hendlerman at yahoo dot com

I understand that it's valid in PHP to overwrite the string with an
array. The problem is that the string is not actually overwritten by
the array. I thought that was clear from the sample code!

Doesn't seem like a feature if the array isn't overwritten. Perhaps I
should have titled = "String is not properly overwritten "

------------------------------------------------------------------------

[2006-09-27 14:54:23] [email]tony2001@php.net[/email]

$string[0] = 'c'; is perfectly valid code and that's what you get with
$string['otherstring'].

------------------------------------------------------------------------

[2006-09-27 14:53:23] [email]derick@php.net[/email]

Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
[url]http://www.php.net/manual/[/url] and the instructions on how to report
a bug at [url]http://bugs.php.net/how-to-report.php[/url]

..

------------------------------------------------------------------------

[2006-09-27 14:47:10] hendlerman at yahoo dot com

Description:
------------
The error is caused by a user error, but I believe PHP should be
throwing an error. PHP is not strongly typed, but I thought you get a
warning if you try to convert a string to an array.

Sorry I am not in 5.1.6


Reproduce code:
---------------
/**
* Output for me
* PHP version 5.1.4
* Array ( [name] => 2alue )
*
* */
function array_bug()
{
echo "PHP version ". phpversion().'<br />';
$test_array = array();

$test_array['name'] = 'value';
$test_array['name']['count'] = 2;

print_r($test_array);
}

array_bug(); exit;

Expected result:
----------------
I would expect an error or warning

Actual result:
--------------
Array ( [name] => 2alue )


------------------------------------------------------------------------


--
Edit this bug report at [url]http://bugs.php.net/?id=38974&edit=1[/url]

[hendlerman at yahoo dot com]

ID: 38974
User updated by: hendlerman at yahoo dot com
-Summary: String is not properly overwritten in
Reported By: hendlerman at yahoo dot com
Status: Open
Bug Type: Arrays related
Operating System: windows XP
PHP Version: 5.1.6
New Comment:

edit title


Previous Comments:
------------------------------------------------------------------------

[2006-09-27 15:32:43] hendlerman at yahoo dot com

Changing title and re-opening so it gets reviewed again.

------------------------------------------------------------------------

[2006-09-27 15:14:18] hendlerman at yahoo dot com

I understand that it's valid in PHP to overwrite the string with an
array. The problem is that the string is not actually overwritten by
the array. I thought that was clear from the sample code!

Doesn't seem like a feature if the array isn't overwritten. Perhaps I
should have titled = "String is not properly overwritten "

------------------------------------------------------------------------

[2006-09-27 14:54:23] [email]tony2001@php.net[/email]

$string[0] = 'c'; is perfectly valid code and that's what you get with
$string['otherstring'].

------------------------------------------------------------------------

[2006-09-27 14:53:23] [email]derick@php.net[/email]

Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
[url]http://www.php.net/manual/[/url] and the instructions on how to report
a bug at [url]http://bugs.php.net/how-to-report.php[/url]

..

------------------------------------------------------------------------

[2006-09-27 14:47:10] hendlerman at yahoo dot com

Description:
------------
The error is caused by a user error, but I believe PHP should be
throwing an error. PHP is not strongly typed, but I thought you get a
warning if you try to convert a string to an array.

Sorry I am not in 5.1.6


Reproduce code:
---------------
/**
* Output for me
* PHP version 5.1.4
* Array ( [name] => 2alue )
*
* */
function array_bug()
{
echo "PHP version ". phpversion().'<br />';
$test_array = array();

$test_array['name'] = 'value';
$test_array['name']['count'] = 2;

print_r($test_array);
}

array_bug(); exit;

Expected result:
----------------
I would expect an error or warning

Actual result:
--------------
Array ( [name] => 2alue )


------------------------------------------------------------------------


--
Edit this bug report at [url]http://bugs.php.net/?id=38974&edit=1[/url]

[tony2001@php.net]

ID: 38974
Updated by: [email]tony2001@php.net[/email]
-Summary: String is not properly overwritten in Multi
Dimensional Arrays
Reported By: hendlerman at yahoo dot com
-Status: Open
+Status: Bogus
Bug Type: Arrays related
Operating System: windows XP
PHP Version: 5.1.6
New Comment:

# php -r '$s = "string"; $s[0] = 3; var_dump($s);'
string(6) "3tring"

This is expected behaviour.



Previous Comments:
------------------------------------------------------------------------

[2006-09-27 15:34:04] hendlerman at yahoo dot com

edit title

------------------------------------------------------------------------

[2006-09-27 15:32:43] hendlerman at yahoo dot com

Changing title and re-opening so it gets reviewed again.

------------------------------------------------------------------------

[2006-09-27 15:14:18] hendlerman at yahoo dot com

I understand that it's valid in PHP to overwrite the string with an
array. The problem is that the string is not actually overwritten by
the array. I thought that was clear from the sample code!

Doesn't seem like a feature if the array isn't overwritten. Perhaps I
should have titled = "String is not properly overwritten "

------------------------------------------------------------------------

[2006-09-27 14:54:23] [email]tony2001@php.net[/email]

$string[0] = 'c'; is perfectly valid code and that's what you get with
$string['otherstring'].

------------------------------------------------------------------------

[2006-09-27 14:53:23] [email]derick@php.net[/email]

Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
[url]http://www.php.net/manual/[/url] and the instructions on how to report
a bug at [url]http://bugs.php.net/how-to-report.php[/url]

..

------------------------------------------------------------------------

The remainder of the comments for this report are too long. To view
the rest of the comments, please view the bug report online at
[url]http://bugs.php.net/38974[/url]

--
Edit this bug report at [url]http://bugs.php.net/?id=38974&edit=1[/url]

[hendlerman at yahoo dot com]

ID: 38974
User updated by: hendlerman at yahoo dot com
Reported By: hendlerman at yahoo dot com
-Status: Bogus
+Status: Open
Bug Type: Arrays related
Operating System: windows XP
PHP Version: 5.1.6
New Comment:

the code you've outlined is not the same as the code I have.

what happens to the key in the array called "count"?


Previous Comments:
------------------------------------------------------------------------

[2006-09-27 15:34:44] [email]tony2001@php.net[/email]

# php -r '$s = "string"; $s[0] = 3; var_dump($s);'
string(6) "3tring"

This is expected behaviour.


------------------------------------------------------------------------

[2006-09-27 15:34:04] hendlerman at yahoo dot com

edit title

------------------------------------------------------------------------

[2006-09-27 15:32:43] hendlerman at yahoo dot com

Changing title and re-opening so it gets reviewed again.

------------------------------------------------------------------------

[2006-09-27 15:14:18] hendlerman at yahoo dot com

I understand that it's valid in PHP to overwrite the string with an
array. The problem is that the string is not actually overwritten by
the array. I thought that was clear from the sample code!

Doesn't seem like a feature if the array isn't overwritten. Perhaps I
should have titled = "String is not properly overwritten "

------------------------------------------------------------------------

[2006-09-27 14:54:23] [email]tony2001@php.net[/email]

$string[0] = 'c'; is perfectly valid code and that's what you get with
$string['otherstring'].

------------------------------------------------------------------------

The remainder of the comments for this report are too long. To view
the rest of the comments, please view the bug report online at
[url]http://bugs.php.net/38974[/url]

--
Edit this bug report at [url]http://bugs.php.net/?id=38974&edit=1[/url]

[tony2001@php.net]

ID: 38974
Updated by: [email]tony2001@php.net[/email]
Reported By: hendlerman at yahoo dot com
-Status: Open
+Status: Bogus
Bug Type: Arrays related
Operating System: windows XP
PHP Version: 5.1.6
New Comment:

It's autoconverted to integer, i.e. 0.


Previous Comments:
------------------------------------------------------------------------

[2006-09-27 15:37:37] hendlerman at yahoo dot com

the code you've outlined is not the same as the code I have.

what happens to the key in the array called "count"?

------------------------------------------------------------------------

[2006-09-27 15:34:44] [email]tony2001@php.net[/email]

# php -r '$s = "string"; $s[0] = 3; var_dump($s);'
string(6) "3tring"

This is expected behaviour.


------------------------------------------------------------------------

[2006-09-27 15:34:04] hendlerman at yahoo dot com

edit title

------------------------------------------------------------------------

[2006-09-27 15:32:43] hendlerman at yahoo dot com

Changing title and re-opening so it gets reviewed again.

------------------------------------------------------------------------

[2006-09-27 15:14:18] hendlerman at yahoo dot com

I understand that it's valid in PHP to overwrite the string with an
array. The problem is that the string is not actually overwritten by
the array. I thought that was clear from the sample code!

Doesn't seem like a feature if the array isn't overwritten. Perhaps I
should have titled = "String is not properly overwritten "

------------------------------------------------------------------------

The remainder of the comments for this report are too long. To view
the rest of the comments, please view the bug report online at
[url]http://bugs.php.net/38974[/url]

--
Edit this bug report at [url]http://bugs.php.net/?id=38974&edit=1[/url]

[hendlerman at yahoo dot com]

ID: 38974
User updated by: hendlerman at yahoo dot com
Reported By: hendlerman at yahoo dot com
Status: Bogus
Bug Type: Arrays related
Operating System: windows XP
PHP Version: 5.1.6
New Comment:

OK.

I can see how this is not a "bug" and expected.
But I think the behaviour should be different. Maybe just:

1. don't loose keys

I can't post to php-dev ATM, but is that the proper place to have this
discussion?


Previous Comments:
------------------------------------------------------------------------

[2006-09-27 15:45:14] [email]tony2001@php.net[/email]

It's autoconverted to integer, i.e. 0.

------------------------------------------------------------------------

[2006-09-27 15:37:37] hendlerman at yahoo dot com

the code you've outlined is not the same as the code I have.

what happens to the key in the array called "count"?

------------------------------------------------------------------------

[2006-09-27 15:34:44] [email]tony2001@php.net[/email]

# php -r '$s = "string"; $s[0] = 3; var_dump($s);'
string(6) "3tring"

This is expected behaviour.


------------------------------------------------------------------------

[2006-09-27 15:34:04] hendlerman at yahoo dot com

edit title

------------------------------------------------------------------------

[2006-09-27 15:32:43] hendlerman at yahoo dot com

Changing title and re-opening so it gets reviewed again.

------------------------------------------------------------------------

The remainder of the comments for this report are too long. To view
the rest of the comments, please view the bug report online at
[url]http://bugs.php.net/38974[/url]

--
Edit this bug report at [url]http://bugs.php.net/?id=38974&edit=1[/url]