ID: 39992
Updated by: [email]nlopess@php.net[/email]
Reported By: [email]nlopess@php.net[/email]
Status: Open
Bug Type: Program Execution
Operating System: linux
PHP Version: 6CVS-2006-12-30 (CVS)
New Comment:

Ah I forgot: removing the "2>&1" part everything works fine.


Previous Comments:
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[2006-12-30 15:52:20] [email]nlopess@php.net[/email]

Description:
------------
With the short reproduce code below, PHP fork()s a new process (sh),
that itself forks a new one (php). proc_terminate() kill()s the sh
process, but the php one doesn't get killed.
I'm not really sure what is causing this problem, but it is breaking
run-tests.php on timeout.

Reproduce code:
---------------
<?php

$cmd='php -r "while(1){}" 2>&1';
$proc = proc_open($cmd, array(), $pipes);
var_dump(proc_terminate($proc));

?>



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Edit this bug report at [url]http://bugs.php.net/?id=39992&edit=1[/url]