A variable in a php statement

[sjmyles]

Hi This works: <?php if (isset($_GET['frm_sortby'])) {
echo '<input type='hidden' name='frm_catid' value='71'>'; } else { echo
'<input type='hidden' name='frm_catid' value='70'>'; } ?> but this doesnt
and I dont know why <?php if
(isset($_GET['frm_sortby'])) { echo '<input type='hidden' name='frm_catid'
value='$HTTP_GET_VARS['frm_catid']'>'; } else { echo '<input type='hidden'
name='frm_catid' value='70'>'; } ?> I'd love some help please.. Simon

[Ross Riley]

Try th following <?php if (isset($_GET['frm_sortby'])) { echo '<input
type='hidden' name='frm_catid' value='$_GET['frm_catid']'>'; } else { echo
'<input type='hidden' name='frm_catid' value='70'>'; } ?> Ross

[sjmyles]

Thanks I tried that but no good - same error message. Parse error: syntax
error, unexpected T_STRING, expecting ',' or ';' in
c:\Inetpub\wwwroot\NewSite\TMPozvqccxam.php on line 196 I have the variable
frm_catid set as a url variable so im a bit stumped

[Michael Fesser]

.oO(sjmyles)

>Thanks I tried that but no good - same error message. Parse error: syntax
>error, unexpected T_STRING, expecting ',' or ';' in
>c:\Inetpub\wwwroot\NewSite\TMPozvqccxam.php on line 196

Hint: You can't put unescaped single quotes into a single quoted string.

Micha