awk print

[David Bear]

I'm using awk to parse a directory listing. I was hoping there is a
way to tell awk to print from $2 - to the end of the columns
available.

find ./ -name '*stuff' | awk '{FS="/" print $3---'}

the $3-- I want to mean -- print from col 3 to the end.

Any awk pros?

--
David Bear
phone: 480-965-8257
fax: 480-965-9189
College of Public Programs/ASU
Wilson Hall 232
Tempe, AZ 85287-0803
"Beware the IP portfolio, everyone will be suspect of trespassing"

[David Bear]

On Wed, Feb 23, 2005 at 11:19:26PM +0100, Roland Smith wrote:

> On Wed, Feb 23, 2005 at 02:40:10PM -0700, David Bear wrote:

> > I'm using awk to parse a directory listing. I was hoping there is a
> > way to tell awk to print from $2 - to the end of the columns
> > available.
> >
> > find ./ -name '*stuff' | awk '{FS="/" print $3---'}

>
> Is this what you mean?:
>
> find ./ -name '*stuff'|sed 's|\.[^/]*/[^/]*/||g'

thanks for the advice. No, this doesn't do what I want.

If I have a directory path /stuff/stuff/more/stuff/more/and/more
that is n-levels deep, I want to be able to cut off the first two
levels and print the from 2 to the Nth level.

>
> Roland
> --
> R.F. Smith /"\ ASCII Ribbon Campaign
> r s m i t h @ x s 4 a l l . n l \ / No HTML/RTF in e-mail
> [url]http://www.xs4all.nl/~rsmith/[/url] X No Word docs in e-mail
> public key: [url]http://www.keyserver.net[/url] / \ Respect for open standards

--
David Bear
phone: 480-965-8257
fax: 480-965-9189
College of Public Programs/ASU
Wilson Hall 232
Tempe, AZ 85287-0803
"Beware the IP portfolio, everyone will be suspect of trespassing"

[Mark Frank]

* On Wed, Feb 23, 2005 at 07:36:05PM -0700 David Bear wrote:

> On Wed, Feb 23, 2005 at 11:19:26PM +0100, Roland Smith wrote:

> > On Wed, Feb 23, 2005 at 02:40:10PM -0700, David Bear wrote:

> > > I'm using awk to parse a directory listing. I was hoping there is a
> > > way to tell awk to print from $2 - to the end of the columns
> > > available.
> > >
> > > find ./ -name '*stuff' | awk '{FS="/" print $3---'}

> >
> > Is this what you mean?:
> >
> > find ./ -name '*stuff'|sed 's|\.[^/]*/[^/]*/||g'

>
> thanks for the advice. No, this doesn't do what I want.
>
> If I have a directory path /stuff/stuff/more/stuff/more/and/more
> that is n-levels deep, I want to be able to cut off the first two
> levels and print the from 2 to the Nth level.

So how about cut?

find ./ -name '*stuff'| cut -d/ -f4-

Mark

--
"The fix is only temporary...unless it works." - Red Green

[Soheil Hassas Yeganeh]

You can set $[1..n] to "" and then print
find ./ -name "stuff" | awk '{ $1=""; $2=""; print}


On Wed, 23 Feb 2005 22:41:32 -0500, Mark Frank <mark@mark-and-erika.com> wrote:

> * On Wed, Feb 23, 2005 at 07:36:05PM -0700 David Bear wrote:

> > On Wed, Feb 23, 2005 at 11:19:26PM +0100, Roland Smith wrote:

> > > On Wed, Feb 23, 2005 at 02:40:10PM -0700, David Bear wrote:
> > > > I'm using awk to parse a directory listing. I was hoping there is a
> > > > way to tell awk to print from $2 - to the end of the columns
> > > > available.
> > > >
> > > > find ./ -name '*stuff' | awk '{FS="/" print $3---'}
> > >
> > > Is this what you mean?:
> > >
> > > find ./ -name '*stuff'|sed 's|\.[^/]*/[^/]*/||g'

> >
> > thanks for the advice. No, this doesn't do what I want.
> >
> > If I have a directory path /stuff/stuff/more/stuff/more/and/more
> > that is n-levels deep, I want to be able to cut off the first two
> > levels and print the from 2 to the Nth level.

>
> So how about cut?
>
> find ./ -name '*stuff'| cut -d/ -f4-
>
> Mark
>
> --
> "The fix is only temporary...unless it works." - Red Green
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>

[FreeBSD questions mailing list]

On 24 feb 2005, at 12:39, Soheil Hassas Yeganeh wrote:

> You can set $[1..n] to "" and then print
> find ./ -name "stuff" | awk '{ $1=""; $2=""; print}
>
>
> On Wed, 23 Feb 2005 22:41:32 -0500, Mark Frank
> <mark@mark-and-erika.com> wrote:

>> * On Wed, Feb 23, 2005 at 07:36:05PM -0700 David Bear wrote:

>>> On Wed, Feb 23, 2005 at 11:19:26PM +0100, Roland Smith wrote:
>>>> On Wed, Feb 23, 2005 at 02:40:10PM -0700, David Bear wrote:
>>>>> I'm using awk to parse a directory listing. I was hoping there is a
>>>>> way to tell awk to print from $2 - to the end of the columns
>>>>> available.
>>>>>
>>>>> find ./ -name '*stuff' | awk '{FS="/" print $3---'}
>>>>
>>>> Is this what you mean?:
>>>>
>>>> find ./ -name '*stuff'|sed 's|\.[^/]*/[^/]*/||g'
>>>
>>> thanks for the advice. No, this doesn't do what I want.
>>>
>>> If I have a directory path /stuff/stuff/more/stuff/more/and/more
>>> that is n-levels deep, I want to be able to cut off the first two
>>> levels and print the from 2 to the Nth level.

>>
>> So how about cut?
>>
>> find ./ -name '*stuff'| cut -d/ -f4-
>>
>> Mark

or if you insist on using awk:

find ./ -name '*stuff' | awk '{for (i=3; i<=NF; i++) printf " %s", $i;
printf "\n" }'

Arno