Yes, probably several ways. Easiest (and possibly most awkward) would be to

add them up individually:

UniqueLetters (calculation, number) = (PatternCount (YourField, "a") > 0) +

(PatternCount (YourField, "b") > 0) + (PatternCount (YourField, "c") > 0) +

....(PatternCount (YourField, "z") > 0)

Another way would be to utilize repeating fields:

Alphabet (global, text, 26 repetitions) - fill each repetition with a

letter from "a" to "z"

LettersUsed (calculation, number, 26 repetitions) = PatternCount (Extend

(YourField), Alphabet) > 0

UniqueLetters (calculation, number) = Sum (LettersUsed)

"Patrick" <Shadow_Rulezhotmail.com> wrote in message

news:a76rgvod04l1bvos17011bpnvkqhfpkv404ax.com...> Question: Is it possible to calculate the unique letters in a string?

> for example boat got 4 unique letters, but feather got 6 unique

> letters from a total of 7 (2 times the 'e') .. is there a way to do

> that?

>

> Thanx,

>

> Patrick

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