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counting duplicates - Microsoft SQL / MS SQL Server

Jane, SELECT field1,count(field1) 'Counter' FROM <tgablename> GROUP BY field1 -- Dinesh. SQL Server FAQ at [url]http://www.tkdinesh.com[/url] "Jane K." <Jane123.com> wrote in message news:00ea01c33f24$e5155960$a301280aphx.gbl... > How can I set up a counter so that whenever there is a > duplicate records, the counter will increase by one. In > other words, I would like to find out how to make the list > looks like this: > > Field 1: Counter: > A 1 > B 1 > C 1 > C 2 > D 1 > E 1 > > Thank you in advance to answer my question. > > ...

  1. #1

    Default Re: counting duplicates

    Jane,

    SELECT field1,count(field1) 'Counter'
    FROM <tgablename>
    GROUP BY field1

    --
    Dinesh.
    SQL Server FAQ at
    [url]http://www.tkdinesh.com[/url]

    "Jane K." <Jane123.com> wrote in message
    news:00ea01c33f24$e5155960$a301280aphx.gbl...
    > How can I set up a counter so that whenever there is a
    > duplicate records, the counter will increase by one. In
    > other words, I would like to find out how to make the list
    > looks like this:
    >
    > Field 1: Counter:
    > A 1
    > B 1
    > C 1
    > C 2
    > D 1
    > E 1
    >
    > Thank you in advance to answer my question.
    >
    >
    >

    Dinesh.T.K Guest

  2. #2

    Default Re: counting duplicates

    Hi

    You don't give the DDL for the table, but if you had a separate Unique Index
    or Primary Key field(s) say PKFld the following sql may work (untested)

    SELECT b.Field1, ( SELECT COUNT(*) FROM MyTable A
    WHERE a.PkFld <= b.PKFld AND a.Field1 =
    b.Field1 ) AS Counter
    FROM MyTable B
    Order by b.Field1, b.PkFld

    John


    "Jane K." <Jane123.com> wrote in message
    news:00ea01c33f24$e5155960$a301280aphx.gbl...
    > How can I set up a counter so that whenever there is a
    > duplicate records, the counter will increase by one. In
    > other words, I would like to find out how to make the list
    > looks like this:
    >
    > Field 1: Counter:
    > A 1
    > B 1
    > C 1
    > C 2
    > D 1
    > E 1
    >
    > Thank you in advance to answer my question.
    >
    >
    >

    John Bell Guest

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