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DataRow[] and Select(filter with a like clause) question - ASP.NET General

I am using the Select method on a DataTable to return a DataRow[] filter = (width LIKE '%width="[1-9][0-9]%') I am getting an exception saying my filter is invalid I narrowed it down to the part that reads [1-9][0-9] if I eliminate this part it works. Is there a way to accomplish what I'm tring to do? Thanks, Ron Vecchi...

  1. #1

    Default DataRow[] and Select(filter with a like clause) question

    I am using the Select method on a DataTable to return a DataRow[]
    filter = (width LIKE '%width="[1-9][0-9]%')

    I am getting an exception saying my filter is invalid
    I narrowed it down to the part that reads [1-9][0-9]

    if I eliminate this part it works.
    Is there a way to accomplish what I'm tring to do?


    Thanks,

    Ron Vecchi


    Ron Vecchi Guest

  2. #2

    Default Re: DataRow[] and Select(filter with a like clause) question

    Heres my filter again, I gave you the Sql version without the escaped ".
    Just to clarify

    filter = width LIKE '%width=\"[1-9][0-9]%'



    "Ron Vecchi" <vencenzocomcast.net> wrote in message
    news:ei%23CC%23DVDHA.1832TK2MSFTNGP09.phx.gbl...
    > I am using the Select method on a DataTable to return a DataRow[]
    > filter = (width LIKE '%width="[1-9][0-9]%')
    >
    > I am getting an exception saying my filter is invalid
    > I narrowed it down to the part that reads [1-9][0-9]
    >
    > if I eliminate this part it works.
    > Is there a way to accomplish what I'm tring to do?
    >
    >
    > Thanks,
    >
    > Ron Vecchi
    >
    >

    Ron Vecchi Guest

  3. #3

    Default DataRow[] and Select(filter with a like clause) question

    I am using the Select method on a DataTable to return a DataRow[]
    filter = (width LIKE '%width="[1-9][0-9]%')

    I am getting an exception saying my filter is invalid
    I narrowed it down to the part that reads [1-9][0-9]

    if I eliminate this part it works.
    Is there a way to accomplish what I'm tring to do?


    Thanks,

    Ron Vecchi


    Ron Vecchi Guest

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