Displaying numbers with 2 digits

[Michael]

Hi,

I have something like :
$c=$a+$b;
echo $c,

The thing is, i want the result to be a 2 digit number (ie 05 and not 5).
How 2 ?

Thanks in advance.

Michael

[Kevin Thorpe]

Michael wrote:

> Hi,
>
> I have something like :
> $c=$a+$b;
> echo $c,
>
> The thing is, i want the result to be a 2 digit number (ie 05 and not 5).
> How 2 ?

$c = $a+$b;
printf('%2u',$c);

...or..

$c = sprintf('%2u',$a+$b);
echo $c;

[Michael Fuhr]

"Michael" <michaperso@easynet.fr> writes:

> I have something like :
> $c=$a+$b;
> echo $c,
>
> The thing is, i want the result to be a 2 digit number (ie 05 and not 5).

See the documentation for printf() and sprintf() in the PHP manual.

[url]http://www.php.net/manual/en/ref.strings.php[/url]
[url]http://www.php.net/manual/fr/ref.strings.php[/url]

--
Michael Fuhr
[url]http://www.fuhr.org/~mfuhr/[/url]

[Pedro Graca]

Michael wrote:

> Hi,
>
> I have something like :
> $c=$a+$b;
> echo $c,
>
> The thing is, i want the result to be a 2 digit number (ie 05 and not 5).
> How 2 ?

+ is an arithmetic operator
[url]http://www.php.net/manual/en/language.operators.arithmetic.php[/url]

I think you want the

.. string operator
[url]http://www.php.net/manual/en/language.operators.string.php[/url]


<?php
$as = "0";
$bs = "5";
$cs = "0";

$an = 0;
$bn = 5;
$cn = 0;

echo $as + $bs; ### 5
echo $as . $bs; ### 05
echo $bs + $cs; ### 5
echo $bs . $cs; ### 50

echo $an + $bn; ### 5
echo $an . $bn; ### 05
echo $bn + $cn; ### 5
echo $bn . $cn; ### 50
?>


Or, if I misunderstood you, use the number_format() or printf()
functions
[url]http://www.php.net/number_format[/url]
[url]http://www.php.net/printf[/url]


HTH

--
..sig

[Michael Fuhr]

Kevin Thorpe <kevin@pricetrak.com> writes:

> Michael wrote:

> >
> > I have something like :
> > $c=$a+$b;
> > echo $c,
> >
> > The thing is, i want the result to be a 2 digit number (ie 05 and not 5).
> > How 2 ?

>
> $c = $a+$b;
> printf('%2u',$c);
>
> ..or..
>
> $c = sprintf('%2u',$a+$b);
> echo $c;

Using %2u results in a leading space, not a leading zero as stated
in the requirement. See the documentation for sprintf() to find
out how to get leading zeros.

--
Michael Fuhr
[url]http://www.fuhr.org/~mfuhr/[/url]

[Michael]

> Using %2u results in a leading space, not a leading zero as stated in

> the requirement. See the documentation for sprintf() to find out how

> to get leading zeros.

It's "%02d"

Thanx folks !