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E Michael Brandt #1
Extension development question
I have spent several frustrating hours trying to make a Command smart
enough NOT to process a document containing malformed html (i.e. html
that does not contain html, head, and body tags, like that in an
Include file.) But it seems that the DW API outfoxes me at every turn:
If I experiment with a document that LACKS those tags, DW *invents*
them so they are present in the document innerHTML, and are present in
the DOM tree as well.
Does anyone know a way around this? Any way to properly detect that a
document lacks any one or all of <html>, <body> and <head> tags?
Thanks.
emichael brandt
E Michael Brandt Guest
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Phil #2 Re: Extension development question
Maybe you could try with a regexp ?
function runCmd(){
var leDOM = dw.getDocumentDOM();
var html = leDOM.getElementsByTagName('html')[0];
var content = html.outerHTML;
var reg = /<html>/gi;
if (reg.test(content)) {
alert('good');
// Process
} else {
alert('bad');
return;
}
window.close();
}
>
> Does anyone know a way around this? Any way to properly detect that a
> document lacks any one or all of <html>, <body> and <head> tags?
>
> Thanks.
>
> emichael brandt
Phil Guest
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E Michael Brandt #3 Re: Extension development question
You hit the nail just right.
I am now using this code and it is working nicely. Thanks:
var h=dw.getDocumentDOM().getElementsByTagName('HTML')[0].outerHTML ;
if (h.search(/<html[^>]*>/i)==-1 || h.search(/<head[^>]*/i) ==-1 ||
h.search(/<body[^>]*/i) ==-1){ ...
It is so interesting to me that the DW API returns a html element and
then does not find "html" in the elements outerHtml.
Similarly I have found that findElementsByTagName('UL'). e.g., will
detect ULs in Included files, but if you then try to check the innerHTML
of one of those UL nodes, DW returns instead the Include directive itself.
Thanks so much for the solution.
emichael brandt
Phil wrote:> Maybe you could try with a regexp ?
>
> function runCmd(){
> var leDOM = dw.getDocumentDOM();
>
> var html = leDOM.getElementsByTagName('html')[0];
> var content = html.outerHTML;
> var reg = /<html>/gi;
>
> if (reg.test(content)) {
> alert('good');
> // Process
>
> } else {
> alert('bad');
> return;
> }
>
> window.close();
> }
>
>
>>>> Does anyone know a way around this? Any way to properly detect that a
>> document lacks any one or all of <html>, <body> and <head> tags?
>>
>> Thanks.
>>
>> emichael brandt
>E Michael Brandt Guest
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