Format a number to any decimal places

[YogeshM]

Hi! I'm having a small problem to format a number to some decimal places and
I'd be glad if someone could please help me solve this issue. e.g. I have 2
numbers number_1 = 100.0052 number_2 = 100.005165665 I need to format
number_2 to the same number of decimal places as number_1, bearing in mind that
number_1 could have 3,4,5 or any number of decimal places. Any idea how to do
this please? This is what I have already done: 1. Get the position of the
decimal place <cfset start = #findNoCase('.',number_1,1)#> 2. Get the number
of decimal places in number_1 <cfset dp = #len(mid(number_1,start +
1,len(number_1)))#> If I <cfouput>No. of decimal places = #dp#</cfoutput>, it
returns 3, 4, 5 etc, depending on the no. of decimal places in number_1 Now
how can i format number_2 to #dp# decimal places? Thanks and regards, Yogesh
Mahadnac.

[MikerRoo]

<cfouput>
#NumberFormat (number_2, '0.#RepeatString ('0', dp)#')#
</cfouput>

[OldCFer]

An easier way to get dp:

<cfset dp = Len(ListLast(number_1,"."))>

[YogeshM]

Thanks!

[MikerRoo]

You're welcome.