Ask a Question related to Macromedia Director Lingo, Design and Development.
-
Robert #1
howto put the same number 36 times in a list?
From the manuals I understand that you make a list with 36 times same
number:
[20, 20, 20, 20, etc.]
Is there some easy operation that does it 36 time for me like:
list=[]
list.add(20)*36
the *36 is just my idea
Anybody a hint how I can do this
thanks,
Robert
Robert Guest
-
Number of times visited
I am using Coldfusion with Microsoft Access database integration to create applications. I am in desperate need for appropriate Coldfusion code so... -
Howto determin the number of elemnts of an array
Hi, how can I determin the number of elements of an array? I saw function array_dims() which returns a string value representing the dimensions of... -
setting number of times Flash plays
I've got a small Flash piece on a website. I want it to play three times and then stop. I've done this in the past and can't remember how, other... -
identify duplicates in an array and number of times duplicated
hi, i have created an array from recordset containing user names eg. (davidp, davidp, evenf, patricka, rebeccah) which i have sorted in... -
HowTo check if my String is a Number (Integer) ?
You can try If IsNumeric(str) Then Convert.ToInt32(str) End If -- Craig Deelsnyder Microsoft MVP - ASP/ASP.NET -
Dan Manes #2
Re: howto put the same number 36 times in a list?
From: "Robert" <weisvisch@xs4all.nl>
I'm not sure if this qualifies as easy, but the best I can come up with> From the manuals I understand that you make a list with 36 times same
> number:
> [20, 20, 20, 20, etc.]
(without using any xtras) would be:
RepeatList = list()
RepeatList[36] = 0
RepeatList = RepeatList + 20
HTH,
-Dan
Dan Manes Guest
-
Robert #3
Re: howto put the same number 36 times in a list?
Dan Manes wrote:
> From: "Robert" <weisvisch@xs4all.nl>
>>>>From the manuals I understand that you make a list with 36 times same
>>number:
>>[20, 20, 20, 20, etc.]
>
> I'm not sure if this qualifies as easy, but the best I can come up with
> (without using any xtras) would be:
>
> RepeatList = list()
> RepeatList[36] = 0
> RepeatList = RepeatList + 20
>
works,
thanks,
Robert
Robert Guest



Reply With Quote

