not (true) not (false)

[SilentBob'secretfusion]

I am having a major brain block. I am reviewing this code and am getting my
logic confused.

This is the code:

<cfif (not refind("\d{3}-\d{3}-\d{4}",form.destinationaddress)) and (not
refind("\d{10}",form.destinationaddress)) >

is this correct?
not(f) and not(f) eq t
not(t) and not(t) eq f
not(f) and not(t) eq t ?

Thanks.

[basky]

I would just change
not(f) and not(t) eq t ?
to
not(f) and not(t) eq f ?

not(f) = true
not(t) = false
t and f = false (1 and 0 = 0)

[OldCFer]

It's:
not(f) and not(f) eq t
not(t) and not(t) eq f
not(f) and not(t) eq f

[Adam Cameron]

Change the logic to be:

if (not (expr1 and expr2));

It's a lot clearer.

I have heard - and certainly believe from my own experience - that humans
struggle with NOTness. So best to minimise the instances of having to do
it :-)

--

Adam

[Adam Cameron]

Or better yet:

<cfif not refind("\d{3}(-?)\d{3}\1\d{4}",form.destinationaddress)>

--

Adam