OpenADefaultComponent keeps returning -2003 error

[Edward de Jong]

I am doing exactly what Apple recommends in Q&A QTMTB56, where I want to
explicitly open a graphics converter component.

I am calling err = OpenADefaultComponent (GraphicsImporterComponentType,
"jpeg", &ci);

I am getting error -2003; i tried the quickdraw type ('qdrw'), but it also
gets the same error. There are no precedent calls necessary to
OpenADefaultComponent, so why in the heck is this not working? I know that
my memory buffer is a JPEG, or PICT, etc., and so I know which codec to ask
for (i remember the codec during the original import of the image).

Can somebody help me here?

[Tom Dowdy]

In article <BB8D55B8.15192%edward@magicmouse.com>,
Edward de Jong <edward@magicmouse.com> wrote:

> I am doing exactly what Apple recommends in Q&A QTMTB56, where I want to
> explicitly open a graphics converter component.
>
> I am calling err = OpenADefaultComponent (GraphicsImporterComponentType,
> "jpeg", &ci);

Are you really passing an OSType as a string?

"jpeg" will result in a pointer to a static string containing the bytes
for "jpeg" whereas 'jpeg' will contain those bytes themselves. You want
'jpeg' and not "jpeg".

This error would have likely been detected at compile time by turning on
higher levels of warnings and errors within your development environment.

The only other thing I could see as a problem would be:
- failure to call EnterMovies() someplace in your application
- running on a system with a minimal install of QuickTime. This could
possibly be the case on OS 9 or Windows, but not on OS X.