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OT: Math help - ASP.NET General

Just divide the width of the page by 2. Then divide the width of the image by 2. Then subtract the length of half of the image from the length of half of the page. This should give you your starting x coordinate. Same thing for the height. I'm assuming that the coordinate system for the image (0,0) is at the top left of the image. Hope that helps. "Mark" <markN0SPAM> wrote in message news:bgrnlh$d0a$1lust.ihug.co.nz... > Hi all, I have a small math problem I am hoping someone can help me with. > > Basically I have to align an ...

  1. #1

    Default Re: Math help

    Just divide the width of the page by 2. Then divide the width of the image
    by 2. Then subtract the length of half of the image from the length of half
    of the page. This should give you your starting x coordinate. Same thing
    for the height. I'm assuming that the coordinate system for the image (0,0)
    is at the top left of the image. Hope that helps.

    "Mark" <markN0SPAM> wrote in message
    news:bgrnlh$d0a$1lust.ihug.co.nz...
    > Hi all, I have a small math problem I am hoping someone can help me with.
    >
    > Basically I have to align an image in the middle of a page but I have to
    > specify the left coordinate for the image.
    >
    > I know the width of the page as well as the width of the image so I just
    > need to work out how far in from the left of the page to specify the image
    > starting point so the image is aligned in the center.
    >
    > Help appreciated :)
    >
    > Cheers
    > Mark
    >
    >

    Joseph D. DeJohn Guest

  2. #2

    Default OT: Math help

    Hi all, I have a small math problem I am hoping someone can help me with.

    Basically I have to align an image in the middle of a page but I have to
    specify the left coordinate for the image.

    I know the width of the page as well as the width of the image so I just
    need to work out how far in from the left of the page to specify the image
    starting point so the image is aligned in the center.

    Help appreciated :)

    Cheers
    Mark


    Mark Guest

  3. #3

    Default Re: Math help

    Cheers everyone, thanks for your help
    Regards
    Mark


    Mark Guest

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