Print current and next three years

[Shaun]

Hi,

I am trying to print the current and next three years in a form. Using the
following code I can only print 2000, 2001, 2002, 2003:

<select name="start_date_year">
<?php
$i = 1;
while ($i <= 4){
if ($i + 1 == date("Y", strtotime($_GET[mysql_date]))){
echo '<option value="'.date("Y", mktime(0, 0, 0, 0, 0, $i)).'"
selected>'.date("Y", mktime(0, 0, 0, 0, 0, $i)).'</option>';
} else {
echo '<option value="'.date("Y", mktime(0, 0, 0, 0, 0,
$i)).'">'.date("Y", mktime(0, 0, 0, 0, 0, $i)).'</option>';
}
$i++;
}
?>
</select>

How can I get this code to start looping from the current year?

Thanks for your help

[Becoming Digital]

<select name="start_date_year">
<?
for( $i=0;$i<3;$i++ ) {
$year = date( 'Y' )+$i;
echo '<option value="'.$year.'">'.$year.'</option>';
}
?>
</select>

Edward Dudlik
Becoming Digital
[url]www.becomingdigital.com[/url]



----- Original Message -----
From: "Shaun" <shaun@mania.plus.com>
To: <php-general@lists.php.net>
Sent: Wednesday, 24 September, 2003 08:29
Subject: [PHP] Print current and next three years


Hi,

I am trying to print the current and next three years in a form. Using the
following code I can only print 2000, 2001, 2002, 2003:

<select name="start_date_year">
<?php
$i = 1;
while ($i <= 4){
if ($i + 1 == date("Y", strtotime($_GET[mysql_date]))){
echo '<option value="'.date("Y", mktime(0, 0, 0, 0, 0, $i)).'"
selected>'.date("Y", mktime(0, 0, 0, 0, 0, $i)).'</option>';
} else {
echo '<option value="'.date("Y", mktime(0, 0, 0, 0, 0,
$i)).'">'.date("Y", mktime(0, 0, 0, 0, 0, $i)).'</option>';
}
$i++;
}
?>
</select>

How can I get this code to start looping from the current year?

Thanks for your help

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