time -l date ==> bash: -l: command not found Bug?

[P. B. S.]

"time" doesn't seem to accept any options. The first thing on the line after "time" is taken as the utility to execute. I need the -l option.
Am I misusing "time" or what?

[Kris Kennaway]

On Fri, Feb 25, 2005 at 04:00:49AM +0200, P. B. S. wrote:

> "time" doesn't seem to accept any options. The first thing on the line after "time" is taken as the utility to execute. I need the -l option.
> Am I misusing "time" or what?
> _______________________________________________

Your shell (apparently bash) provides a builtin time function. If
you want to use FreeBSD's time(1) binary, call it by absolute path
(/usr/bin/time)

Kris

[Parv]

in message <20050225020659.GA75395@xor.obsecurity.org>,
wrote Kris Kennaway thusly...

>
> On Fri, Feb 25, 2005 at 04:00:49AM +0200, P. B. S. wrote:

PBS, Do wrap lines around 69 or so characters to give me no
incentive to ignore your mail otherwise.

> > "time" doesn't seem to accept any options. The first thing on
> > the line after "time" is taken as the utility to execute. I need
> > the -l option. Am I misusing "time" or what?

>
> Your shell (apparently bash) provides a builtin time function. If
> you want to use FreeBSD's time(1) binary, call it by absolute path
> (/usr/bin/time)

Look also in bash(1) man page which states somewhere to use '\' in
order to use the real command (as it appears in $PATH of course) and
avoid built-in/alias.


- Parv

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