Variable in variable name?

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  1. #1

    Default Variable in variable name?

    Apparently there is a way to reference a variable from a variable

    something like:

    $name = "Variable";
    for ($i = 0, $i <= 50, $i++)
    {
    $name$i = rand(); //create a variable called 'Variable1', 'Variable2',
    'Variable3' ........ 'Variable 50'
    echo $name$i . "<br>";
    }


    I can't find anything on php.net on how to do this... someone once told me
    it was with $$varname...
    Any help?

    Thanks




    Kevin Torr Guest

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  3. #2

    Default Re: Variable in variable name?

    "Kevin Torr" <kevintorr@hotmail.com> wrote:
    > Apparently there is a way to reference a variable from a variable
    >
    > something like:
    >
    > $name = "Variable";
    > for ($i = 0, $i <= 50, $i++)
    > {
    > $name$i = rand(); //create a variable called 'Variable1',
    > 'Variable2',
    > 'Variable3' ........ 'Variable 50'
    > echo $name$i . "<br>";
    > }
    >
    >
    > I can't find anything on php.net on how to do this... someone once
    > told me it was with $$varname...
    [url]http://uk.php.net/manual/en/language.variables.variable.php[/url]

    HTH;
    JOn
    Jon Kraft Guest

  4. #3

    Default Re: Variable in variable name?


    "Kevin Torr" <kevintorr@hotmail.com> wrote in message
    news:4045bfbf$0$27650$61ce578d@news.syd.swiftdsl.c om.au...
    > Apparently there is a way to reference a variable from a variable
    >
    > something like:
    >
    > $name = "Variable";
    > for ($i = 0, $i <= 50, $i++)
    > {
    > $name$i = rand(); //create a variable called 'Variable1', 'Variable2',
    > 'Variable3' ........ 'Variable 50'
    > echo $name$i . "<br>";
    > }
    >
    >
    $name = "Variable";
    for ($i=0; $i<=50; $i++)
    {

    ${$name.$i} = rand();

    }

    echo $Variable3;


    Kreso Guest

  5. #4

    Default Re: Variable in variable name?

    use eval()?
    Unregistered Guest

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