XOR operator?

[Daniel Carrera]

Hi all,

I'm trying to figure out what the boolean "xor" operator is in Ruby. I
thought it was "^^" but that doesn't work. I searched through PickAxe and
couldn't find a mention of xor.

Does Ruby have an xor?

Cheers,
--
Daniel Carrera | OpenPGP KeyID: 9AF77A88
PhD grad student. |
Mathematics Dept. | "To understand recursion, you must first
UMD, College Park | understand recursion".

[Mark J. Reed]

On Wed, Oct 29, 2003 at 05:36:01AM +0900, Daniel Carrera wrote:

> Hi all,
>
> I'm trying to figure out what the boolean "xor" operator is in Ruby. I
> thought it was "^^" but that doesn't work. I searched through PickAxe and
> couldn't find a mention of xor.
>
> Does Ruby have an xor?

The xor operator in Ruby is ^ (just one). It serves as both bitwise
and Boolean, depending on its arguments:

irb(main):001:0> 2 ^ 1
=> 3
irb(main):002:0> true ^ false
=> true
irb(main):003:0> true ^ true
=> false

-Mark

[gabriele renzi]

il Wed, 29 Oct 2003 05:36:01 +0900, Daniel Carrera
<dcarrera@math.umd.edu> ha scritto::

>Hi all,
>
>I'm trying to figure out what the boolean "xor" operator is in Ruby. I
>thought it was "^^" but that doesn't work. I searched through PickAxe and
>couldn't find a mention of xor.

it is just one ^

>> 0b0000^0b0111

=> 7

[Lyle Johnson]

Daniel Carrera wrote:

> I'm trying to figure out what the boolean "xor" operator is in Ruby. I
> thought it was "^^" but that doesn't work.

It's just a single "^" character, e.g.

six = 2 ^ 4

Hope this helps,

Lyle

[Jim Freeze]

On Wednesday, 29 October 2003 at 5:36:01 +0900, Daniel Carrera wrote:

> Hi all,
>
> I'm trying to figure out what the boolean "xor" operator is in Ruby. I
> thought it was "^^" but that doesn't work. I searched through PickAxe and
> couldn't find a mention of xor.
>
> Does Ruby have an xor?

irb(main):001:0> 1 ^ 0
=> 1
irb(main):002:0> 1 ^ 1
=> 0
irb(main):003:0> 0 ^ 0
=> 0
irb(main):004:0> 0 ^ 1
=> 1


--
Jim Freeze
----------
The Roman Rule
The one who says it cannot be done should never interrupt the
one who is doing it.

[Dalibor Sramek]

On Wed, Oct 29, 2003 at 05:36:01AM +0900, Daniel Carrera wrote:

> I'm trying to figure out what the boolean "xor" operator is in Ruby. I
> thought it was "^^" but that doesn't work. I searched through PickAxe and
> couldn't find a mention of xor.

Neither Ruby in a Nutshell mentions one. However I made a quick tests and it
seems it is safe to use ^ for integers.

Dalibor

--
Dalibor Sramek [url]http://www.insula.cz/dali[/url] | In the eyes of cats,
[email]dalibor.sramek@insula.cz[/email] | all things belong to cats.

[Daniel Carrera]

Thanks everyone. Yeah, ^ seems to work.



On Tue, Oct 28, 2003 at 03:04:04PM -0600, Lyle Johnson wrote:

> Daniel Carrera wrote:
>

> >I'm trying to figure out what the boolean "xor" operator is in Ruby. I
> >thought it was "^^" but that doesn't work.

>
> It's just a single "^" character, e.g.
>
> six = 2 ^ 4
>
> Hope this helps,
>
> Lyle

--
Daniel Carrera | OpenPGP KeyID: 9AF77A88
PhD grad student. |
Mathematics Dept. | "To understand recursion, you must first
UMD, College Park | understand recursion".

[Dave Thomas]

On Oct 28, 2003, at 14:36, Daniel Carrera wrote:

> Hi all,
>
> I'm trying to figure out what the boolean "xor" operator is in Ruby. I
> thought it was "^^" but that doesn't work. I searched through PickAxe
> and
> couldn't find a mention of xor.
>

[url]http://www.rubycentral.com/book/ref_c_falseclass.html#FalseClass._up[/url]
[url]http://www.rubycentral.com/book/ref_c_fixnum.html#Fixnum.Bitoperations[/url]

etc

[Josef 'Jupp' Schugt]

* Daniel Carrera; Wed, 29 Oct 2003 06:28:45 +0900

> Thanks everyone. Yeah, ^ seems to work.

[...as an XOR operator]

One should add that the exponentiation operator is '**'.
Matz, does that syntax mean that Ruby also has COBOL or FORTRAN
heritage (I am not aware of anything else that would justify that
assumption)?

Josef 'Jupp' Schugt

[Mark J. Reed]

On Tue, Oct 28, 2003 at 11:21:33PM +0000, Josef 'Jupp' Schugt wrote:

> One should add that the exponentiation operator is '**'.
> Matz, does that syntax mean that Ruby also has COBOL or FORTRAN
> heritage (I am not aware of anything else that would justify that
> assumption)?

AFAIK, Ruby got it from Perl, which got it from Fortran, only because
C has no exponentiation operator and ^ was taken by XOR.

-Mark